Question

Please tell me the answer of these

Answer 1

1. Let x, y and z are multiple of 6 then

6x, 6y and 6z are these numbers

as given

6x +6y +6z = 666

2. Let the number be x,

as given 3/4 of a number is 3/4*x

and 1/3 of that number is 1/3*x

3/4*x = 1/3 + 60

3. Let the number be x,

as given 10 times of a number is 10x

so x+10x = 264

4. Let two numbers be x and y then

as given ratio of these number be 4:7

then x:y = 4:7 >>>> x/y = 4/7

Now both the numbers are increased by 4 then the ratio is 3:5

so x +4: y+4 = 3:5 >>>> x+4/y+4 = 3/5