Question

Please tell me the answer of this..​

Answer 1

Answer:

hey here is your solution

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Step-by-step explanation:

let the required fraction be x/y

wherein numbmerator be x and that of denominator be y

so according to first condition

y=x+8 (1)

according to the second condition

x+7/y+7=3/4

ie 4(x+7)=3(y+7)

so 4x+28=3y+21

ie 4x-3y=-7 (2)

substituting value of y from (1) in (2)

we get

4x-3(x+8)=-7

so 4x-3x-24=-7

ie x=17

substituting value of x in any of two equations

we get

y=25

so our assumed fraction=x/y

=17/25

thus our required rational number is 17/25

Answer 2

Answer:

• The original rational number is 7/15

Step-by-step explanation:

Given:-

• Denominator of a rational number exceeds its numerator by 8
• If 7 is added to its numerator and denominator, then the number 3/4

To Find:-

• The original rational number

Assumptions:-

• Let the numerator of the fraction be x
• Let the denominator of the fraction be x + 8

Solution:

✰ The original fraction will be,

$\rightarrow \qquad \tt \dfrac{x}{x+8}$

✰ According to the question,

$\rightarrow \qquad \tt \dfrac{x+7}{x+8+7} = \dfrac{3}{4}$

$\rightarrow \qquad \tt \dfrac{x+7}{x+15} = \dfrac{3}{4}$

✰ Cross Multiplying we get,

$\rightarrow \qquad \tt 4( x+ 7 ) = 3 ( x + 15 )$

$\rightarrow \qquad \tt 4x + 28 = 3x + 45$

$\rightarrow \qquad \tt 4x - 3x = 45 - 28$

$\rightarrow \qquad \tt {\blue{\boxed{\frak{ x = 17}}}\pink\bigstar}$

✰ The original fraction will be,

$\nrightarrow \qquad \sf Numerator = x = 17$

$\nrightarrow \qquad \sf Denominator = x + 8 = 25$

Therefore :

• ${\purple{\underline{\boxed{\tt{Original \; Fraction = \dfrac{17}{25} }}}\bigstar}}$

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