Question

please tell me the answer of this question​

Answer 1

Answer:

130

Step-by-step explanation:

Given,

1st term(a)= 4

Common difference(d)=6-4=2

And n=10     [ Since we need to find the sum of first 10 terms]

Now,

We know,

S=n/2[2a+(n-1)d]

S=10/2[2(4)+9(2)]

S=5[8+18]

S=130

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Answer 2

Answer:

$a1 = 4 \\ a2 = 6 \\ = d = a2 - a1 \\ = 6 - 4 \\ = 2 \\ tenth \: term = a + 9d \\ 4 + 9 \times 2 \\ = 4 + 18 \\ = 22$