Question

please tell me the answer of this question with explanation​

Answer 1

Answer:

a^6+b^6+3a^4b^2+3a^2b^4=a^6+b^6+2a^3b^3

3a^2b^2(a^2+b^2)=2a^3b^3

a^2+b^2=2ab/3

a/b+b/a=2/3

Answer 2

$\bf \underline{✭ Given:-}$

• (a² + b²)³ = (a³ + b³)²

$\bf \underline{✭ To Find :-}$

• $\frac{a}{b} + \frac{b}{a} = \: ?$

$\bf \underline{✭Solution:-}$

$\large(a² + b²)³ = (a³ + b³)²$

✯ On Expanding these by using Identities

$a {}^{6} + b^{6} + 3a {}^{2}b {}^{2}(a {}^{2} + b {}^{2} ) = a {}^{6} + b{}^{6} \: + 2a {}^{3} b {}^{3} \\ \\ ★ \: \: Using \: \: (a+b)³ = a³ + b³ +3ab(a+b) \\ (a+b)² = a² +b² +2ab \\ \\ ➩ \: 3a {}^{2} b {}^{2} (a {}^{2} + b {}^{2} ) = 2a {}^{3} b {}^{3} \\ \\ ➩ \: 3a {}^{2} b {}^{2} (a {}^{2} + b {}^{2} ) = 2ab(a {}^{2} b {}^{2} ) \\ \\ ➩3(a {}^{2} + b {}^{2} ) = 2ab \\ \\ ➩ \frac{a {}^{2} + b {}^{2} }{ab} = \frac{2}{3} \\ \\ ➩ \: \frac{a {}^{2} }{ab} + \frac{b {}^{2} }{ab} = \frac{2}{3} \\ \\ ➩ \: \frac{a}{b} + \frac{b}{a} = \frac{2}{3}$

$\Large\underline{Hence, \: the \: \: value \: \: of \: \frac{a}{b} + \frac{b}{a} = \frac{2}{3}}$