please tell me the answer please fast
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3
OP_|_AB
so,
x+y+z=90°---(1)
now,
let x,y and z be a, 3a, 5a respectively
from (1)
x+y+z=90°
a+3a+5a=90°
9a=90°
a=10°
so,
x=a=10°
y=3a=30°
z=5a=50°
so,
x+y+z=90°---(1)
now,
let x,y and z be a, 3a, 5a respectively
from (1)
x+y+z=90°
a+3a+5a=90°
9a=90°
a=10°
so,
x=a=10°
y=3a=30°
z=5a=50°
Answered by
3
In yhis questin it is given that PQ is perpendicular to AB.
so,
angle x+angley+angle z=90
now,
let x be involved in the ratio
then,
angle x=1x
angle y=3x
angle z=5x
A/Q
1x+3x+5x=90
9x=90
x=10
so,
angle x=1×10=10
angle y=3×10=30
angle z=5×10=50
==================================
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PLZ MARK AS BRAINLIEST IF YOU GET YOUR ANSWER.
so,
angle x+angley+angle z=90
now,
let x be involved in the ratio
then,
angle x=1x
angle y=3x
angle z=5x
A/Q
1x+3x+5x=90
9x=90
x=10
so,
angle x=1×10=10
angle y=3×10=30
angle z=5×10=50
==================================
HOPE YOU LIKE IT
PLZ MARK AS BRAINLIEST IF YOU GET YOUR ANSWER.
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