Question

please tell me the answer please tell me​

Answer 1

it will be 1cm , what is your answer ?

Answer 2

Given :

1) O be the center of the circle.

2) Length of diameter of circle =5cm. l(AD)

3) Length of chord = 4cm. l(AB)

To find,

The distance between the chord and the center of the circle. l(OC)

Solution :

Radius = 1/2 x diameter

AO = 1/2 x AD

AO = 1/2 x 5

AO = 2.5

AC = 1/2 x AB

AC = 1/2 x 4

AC = 2cm

Segment joining to the midpoint of the chord is perpendicular bisector of chord.

Therefore, angle OCA = 90°.

In triangle OCA, Side opposite to right angle is AO Is Hypotenuse.

Now, we have AO and AC.

By Pythagoras theorem,

(Hypotenuse)^2=(Side 1)^2+(Side 2)^2

(AO)^2 = (OC)^2+(AC)^2

(2.5)^2 = (OC)^2+(2)^2

(6.25) = (OC)+(4)

(6.25 - 4 ) = (OC)

(2.25) = (OC)

Therefore, (OC) = 2.25.

[ So, the distance between the chord and the center of the circle is 2.25cm. ]