Question

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Answer 1

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From the following figure:-

BC and CD are in series connection

Let, the resistance be R1 for series connection BC and CD

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R1 ➝ (BC + CD)

➝ 10 ohm + 10 ohm

➝ 20 ohm

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Now, according to given figure:-

R1 and BD are in parallel connection

Let, the resistance be R2 for parallel connection R1 and BD

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R2 ➝ (1/R1 + 1/BD)

➝ 1/20 + 1/10

➝(1+2)/20

➝3/20 ohm

So, Resultant resistance =>3/20 ohm

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Now, Voltage => 6v {given}

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OHM's law:-

V=IxR

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•°• 6 = I x 3/20

➝ I = 6 x 20/3

➝ I = 2 x 20

➝ I = 40A

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Hence, I = 40A

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