Please tell me the answer Tan(b+c/2)=cota/2
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Hey, here is your answer.
LHS;
In a Triangle ABC,
Angle A+ANGLE B+Angle C=180°
1/2 Angle A+ANGLE B+Angle C=1/2 *180°
Angle B+Angle C/2=90°- angle A/2. _(1)
Now,IN LHS:
tan(b+c/2) can be written as,
tan(90-a/2)
or cot(a/2). [using identity tan(90-x)=cotx]
HENCE, PROVED
LHS;
In a Triangle ABC,
Angle A+ANGLE B+Angle C=180°
1/2 Angle A+ANGLE B+Angle C=1/2 *180°
Angle B+Angle C/2=90°- angle A/2. _(1)
Now,IN LHS:
tan(b+c/2) can be written as,
tan(90-a/2)
or cot(a/2). [using identity tan(90-x)=cotx]
HENCE, PROVED
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