Question

please tell me the answer with full explanation​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Question 18 .A.

By applying Pythagoras theorem in ∆ ABC

(AC)² + (BC)² = (AB)²

(BC)² = (AB)² – (AC)²

(BC)² = (25)² – (7)²

(BC)² = 625 – 49 = 576

BC = 24cm

Question 18 .B.

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)² + (AB)² + (BC)²

⇒(AC)² = (12)² + (5)²

⇒(AC)² = 144 + 25

⇒(AC)² = 169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.

Question 19

To construct: An isosceles triangle PQR whrere PQ=RQ=6.5cm and ∠Q=110°

Steps of construction:

(a) Draw a line segment QR=6.5cm

(b) At point Q, draw an angle of 110°

with the help of protractor, i.e., ∠YQR=110°

(c) Taking Q as centre, draw an arc with radius 6.5cm which cuts QY at point P

(d) Join PR

It is the required isosceles triangle PQR