Question

please tell me the area of the quadrilateral​

Answer 1

Answer:

AP =6. by Pythagoras theorem

area of ABCD= ar of BCPQ. +ar ofAPB. +. ar of QDC

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Answer 2

The quadrilateral is a trapezium,therefore Area=

$\frac{1}{2} (height)(sum \: of \: parallel \: sides)$