Question

please tell me the correct answer ​

Answer 1

Step-by-step explanation:

Given

Let ABCD (HOPE) be the quadrilateral circumScribing the circle with center O. The quadrilateral touches the circle at point P, Q, R, & S.

TO PROVE : AB+CD=AD+BC

PROOF:

From theorem 10.2 ; lengths of tangents drawn from external Point are equal.

Hence,

AP=AS............... (1)

BP=BQ..................(2)

CR=CQ...............(3)

DR=DS..............(4)

adding (1)+(2)+(3)+(4)

AP+NP+CR+DR=AS+BQ+CQ+DS

(AP+BP) +(CR+DR) =(AS+DS) +(BQ+CQ)

AB +CD=AD+BC

HENCE PROVED.