Question

please tell me the correct answer friendl 10 std​

Answer 1

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a}$

1. i)

$x = \frac{ - ( - 8)± \sqrt{ {( - 8)}^{2} - 4(3)( - 3)} }{2(3)} \\ \\ x = \frac{8±10}{6} \\ \\ x = \frac{18}{6} = 3 \\ \\ x = \frac{ - 2}{6} = \frac{ - 1}{3}$

ii)

$x = \frac{ - ( - 11)± \sqrt{ {( - 8)}^{2} - 4(2)(9)} }{2(2)} \\ \\ x = \frac{11±7}{4} \\ \\ x = \frac{18}{4} = \frac{9}{2} \\ \\ x = \frac{4}{4} = 1$

2.

$\frac{x + 3}{x + 2} = \frac{3x - 7}{2x - 3}$

$(x + 3)(2x - 3) = (3x - 7)(x + 2)$

$2 {x}^{2} - 3x + 6x - 9 = 3 {x}^{2} + 6x - 7x - 14 \\ {x}^{2} - 4x - 5 = 0$

$x = \frac{ - ( - 4)± \sqrt{ {( - 4)}^{2} - 4(1)( - 5) } }{2(1)} \\ \\ x = \frac{4±6}{2} \\ \\ x = \frac{10}{2} = 5 \\ \\ x = \frac{ - 2}{2} = - 1$