Question

please tell me the formula for vant hoff factor, degree of dissociation and dissociation constant in terms of i, n and alpha??​

Answer 1

Answer:

Taking into account Van't Hoff factor, the formula for depression of freezing point is, ∆Tf = if Thus, 0.201 = i x 1.86 x 0.10 So, i = 1.08. Thus the Van't Hoff factor value will be 1.08