Math, asked by kakawaljeet, 1 year ago

Please tell me the identity of sin~1 {x - y} [sin inverse (x - y)]

Answers

Answered by rahul200013
1

 { \sin(( x \times  \sqrt{1 -  {y}^{2} } )   - ( \sqrt{1 -  {x}^{2} }   \times y) ) }

this is the required formula just replace sin in this formula with sin inverse

Similar questions