Question

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The length breadth and height of a room are 8 m 25 CM 6 m75 cm and 4 m 50 cm respectively. Determine the longest tape which can measure the three dimensions of the room exactly​

Answer 1

Answer:

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Explanation:

Correct option is

D

75 cm

Length = 825 cm =3×5×5×11

Breadth = 675 cm =3×3×3×5×5

Height = 450 cm =2×3×3×5×5

Longest tape = HCF of 825, 675, and 450 =3×5×5=75cm

Therefore, the longest tape is 75 cm.

Answer 2

Explanation:

Length of room = 8m 25cm = 825 ᴄᴍ

Breadth of room = 6m 75m = 675 ᴄᴍ

Height of room = 4m 50m = 450 ᴄᴍ

∴ The required longest rod = HCF of 825, 675

and 450 First consider 675 and 450

By applying Euclid’s division ʟᴇᴍᴍᴀ

675 = 450 × 1 + 225 450

= 225 × 2 + 0

∴ HCF of 675 and 450 = 825

Now consider 625 and 825 By applying Euclid’s division lemma

825 = 225 × 3 + 150

255= 150 × 1 + 75

150= 75 × 2 + 0

HCF of 825, 675 and 450 = 75