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Given: ABCD is a rhombus in which AB = BC = CD = AD. Therefore, ,from (1) and (2) we can say that diagonals of a rhombus bisect each other. Sol: Given that ABCD is a rhombus then AB = BC = CD = AD.
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31)C
32)D
33)A
34)C
35)D
36)A
37)B
38)C
39)C
40)A
41)C
42)A
43)B
44)A
45)
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