Question

Please tell me the solution of this problem. It's very urgent​

Answer 1

Answer:

let the consecuitive integers be = x, x+2

(1/9)x+2 = (1/5)x + 2

(x+2)/9 = x/5 + 2

(x+2)/9 = (x + 10 )/5

5x + 10 = 9x + 90

4x = 80

x = 20

Answer 2

Step-by-step explanation:

Given that;-

Two consecutive odd numbers such that one fifth of the smaller exceeds one ninth of the greater by 2.

To find:

Find the two consecutive odd numbers.

Solution:-

Let the Consecutive odd numbers be X and X+2

Greater number = X+2

smaller number = X

One - fifth of the smaller number = (1/5)X=X/5

One - ninth of the greater number

= (1/9)(X+2)

=> (X+2)/9

One fifth of the smaller exceeds the one ninth of the greater by 2

=>X/5=(X+2)/9+2

=>X/5-(X+2)/9=2

LCM of 5 and 9 is 45

=>[9X-5(X+2)]/45=2

=>(9X-5X-10)/45=2

=> (4X-10)/45=2

=>4X-10= 2×45

=>4X-10=90

=>4X=90+10

=>4X=100

=>X=100/4

=>X=25

=>X+2=25+2=27

Answer:-

The required two consecutive odd numbers are 25 and 27

Check:-

27>25

One fifth of the smaller =25/5=5

One ninth of the greater =27/9=3

One ninth of the greater+2=3+2=5

=One fifth of the smaller.