please tell me the solution of this question
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given zero of the given polynomial is -3
so. p(-3)=0
(k-1)(-3)²+k(-3)+1=0
9k-9-3k+1=0
6k-8=0
6k=8
k=4/3
so. p(-3)=0
(k-1)(-3)²+k(-3)+1=0
9k-9-3k+1=0
6k-8=0
6k=8
k=4/3
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tq
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