Question

please tell me the solution of this question

Answer 1

Given : ACDE & BCGF are square on side AC & BC

To Prove : ∆BCD and ∆ACG are congruent
AG =BD

Proof:
angle ACG= angle ACB + angle BCG
=angle ACB +90°

angle BCD=angle ACB + angle ACD
= angle ACB +90°



angle ACG = angle BCD ( by proof)

IN ,∆BCD and ∆ACG
BC=CG (side of same square)
CD=AC (side of same square)
angle ACG = angle BCD ( by proof)
therefore ∆BCD congruent to ∆ ACG by SAS Congruency rule

AG = BD (corresponding parts of congruent ∆ )

Hence proof