Question

please tell me the solution set
x^2 - 5 < 4​

Answer 1

Step-by-step explanation:

$x {}^{2} - 5 < 4 \\ \\ x {}^{2} < 4 + 5 \\ \\ x {}^{2} < 9 \\ \\ x < \sqrt{9} \\ \\ \\ x < + - 3$

SO X=+-(3)

Answer 2

Answer:

−5<4

−5<4x

−5<4x 2

−5<4x 2 <4+5

−5<4x 2 <4+5x

−5<4x 2 <4+5x 2

−5<4x 2 <4+5x 2 <9

−5<4x 2 <4+5x 2 <9x<

−5<4x 2 <4+5x 2 <9x< 9

−5<4x 2 <4+5x 2 <9x< 9

−5<4x 2 <4+5x 2 <9x< 9

−5<4x 2 <4+5x 2 <9x< 9 x<+−3

−5<4x 2 <4+5x 2 <9x< 9 x<+−3

−5<4x 2 <4+5x 2 <9x< 9 x<+−3

−5<4x 2 <4+5x 2 <9x< 9 x<+−3 SO X=+-(3)