Question

please tell me this answer​

Answer 1

Answer:

i) 45 m

ii) 30 m/s

Explanation:

Given:

• Initial Velocity (u) = 0 m/s

• Time taken (t) = 3 seconds

• Acceleration (a) = g = 10 m/s²

i) Height from which the ball was dropped, i.e., distance covered (s).

We can find the distance by using the 2nd formula of motion.

s = ut + 1/2at²

⇒ s = 0 + (1/2 * 10 * 3 * 3)

⇒ s = 45 m

Hence, the ball was dropped from a height of 45 m.

ii) Velocity of the ball at the time of hitting the ground, i.e., final velocity (v).

We can find the final velocity by using the 1st formula of motion.

v = u + at

⇒ v = 0 + (10 * 3)

⇒ v = 30 m/s

Hence, the velocity of the ball at the time of hitting the ground was 30 m/s.

The other formula we could have used (the 3rd formula of motion):

v² = u² + 2as

Hope it helps!