Question

please tell me this question​

Answer 1

Answer:

if 4 tano=3

evaluvate 4sino-caso+1

                 4sino+caso_1

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

I will write O for theta

$4\tan O =3\\tan\ O = \frac{3}{4}$

by identity

$1+tan^2O = sec^2O\\sec\ O = \frac{5}{4}\\cos O = \frac{4}{5}$

by another identity

$sin^2O+cos^2O=1\\sin^2O+\frac{16}{25}=1\\sinO=\frac{3}{5}$

Now, we will solve the equation

$\frac{4sinO-cosO+1}{4sinO+cosO-1}\\\\=\frac{\frac{12}{5}-\frac{4}{5}+\frac{5}{5}}{\frac{12}{5}+\frac{4}{5}-\frac{5}{5}}\\\\=\frac{12-4+5}{12+4-5}\\\\=\frac{13}{11}$

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