please tell me this question
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safiasaheb:
would just mark the sides of the triangle so that i could be more clear in answering your doubt?
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x
=180- ( 40+40)
= 180-80
= 100
[ base angles of an isosceles triangle are equal and by angle sum property x = 100]
x + (the adjacent angle) = 180°
[ linear pair]
Let that adjacent angle be a
a
= 180 - x
= 180 - 100
= 80°
y
= 180-(80 + 80)
= 180- 160
= 20°
[ base angles of an isosceles triangle are equal and by angle sum Property y = 20°
hope it helps
=180- ( 40+40)
= 180-80
= 100
[ base angles of an isosceles triangle are equal and by angle sum property x = 100]
x + (the adjacent angle) = 180°
[ linear pair]
Let that adjacent angle be a
a
= 180 - x
= 180 - 100
= 80°
y
= 180-(80 + 80)
= 180- 160
= 20°
[ base angles of an isosceles triangle are equal and by angle sum Property y = 20°
hope it helps
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