Question

Please tell me this question ​

Answer 1

Step-by-step explanation:

Lt {(8x -3)/(2x-1) - (4x^2 +1)/(4x^2 -1)

x -> 1/2

{(8x -3)(2x+1)/(2x+1)(2x-1) -

(4x^2+1) (1)/(2x+1)(2x-1)}

{ (16x^2 + 8x - 6x- 3)/(2x+1)(2x-1)-

(4x^2 +1)/ (2x+1)(2x -1)}

{ (16x^2 + 2x + 3) - (4x^2 +1)}/(2x+1)(2x-1)

{12x^2 + 2x +2} /(2x +1)(2x -1)

12x^2 +6x -4x + 2

6x (2x +1) - 2(2x +1)

(6x - 2)(2x +1)/(2x-1)(2x+1)

(6x - 2)/(2x -1) = 6× 1/2 -2 = 1/0 Undefined

Answer 2

Answer:

your solution is in above pics

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