Question

please tell me this question

Answer 1

Given,

Area of the base of the cylinder = 616 cm².
Height of the cylinder = 2.5 cm.
Volume of the cylinder = V .

$V = \pi {r}^{2} h$
$\pi {r}^{2} = area \: of \: the \: base \: circle \\ of \: the \: cylinder.$

So, volume of the cylinder:

= Area of the base circle of the cylinder * height of the cylinder.

= 616*2.5

$= 1540 \: {cm}^{3}$
$volume \: of \: the \: cylinder \\ = 1540 {cm}^{3}$

Answer 2

Volume of cylinder = πr^2h
Then base of Cylinder =616 Cm^2
πr^2=616
[22/7]xr^2 = 616
r^2 =616x7/22
r^2 = 196
r^2 = 14^2
r = 14
Now
Volume=22/7x 14^2 x2.5
= 1540cm^3