Question

Please tell me this question answer with explanation as early as possible​

Answer 1

Answer:

Let A be the area of ∆ABC and a,b and c denote the lengths of the sides of this triangle.

Let 2s=a+b+c.

Given altitudes of the triangle are 3,4 and 5.

Thus 2A=3a=4b=5c=>a=2A/3,b=2A/4

and c=2A/5

Using formula A^2=s(s-a)(s-b)(s-c) and put s=47A/60 and values of a,b and c in terms of A we get

A=3600/358.7

Answer 2

Answer:

Let

sides are- a,b,c

ATQ

2s=a+b+c

again

=>2A=3a=4b=5c

=>a=2A/3

b=2A/4

c=2A/5

According to formula,

A=

$\sqrt{s(s - a)(s - b)(s - c)}$

=>A=3.008

or 358.7

Step-by-step explanation:

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