Question

please tell me this solution​

Answer 1

Answer:

Given: ABC is an isosceles triangle with AB = AC and D is a point on BC such that BD = DC.

To prove that: AD bisects <A.

Proof: In ΔABD and ΔACD

AB = AC [given]

BD = DC [given]

AD is common.

So ΔABD and Δ ACD are congruent [By SSS rule]

Therefore <BAD = <CAD or AD bisects <A.

QED

Step-by-step explanation: please mark me brainliest pls

Answer 2

Answer:

first we will congruence the triangle and then by congruence both proved