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Given : ΔABC is equilateral triangle
∠DAC = ∠EBC
and C is the midpoint between DE so, DC = EC
Prove that : ΔDAC ≅ ΔEBC
proof : ΔDAC and ΔEBC
DC = EC (given)
∠DAC = ∠EBC (given)
AC = BC (ΔABC is equilateral triangle ,so AB = BC = AC)
by S.A.S ΔDAC ≅ ΔEBC are congruent
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