Please tell me to check the correctness of the relation h =rpg2S for the height of liquid of density 'p' and surface tension 'S' , raised in the capillary tube of radius 'r' and angle of contact zero with the liquid, if incorrect then deduce the correct form.
Answers
The surface of a liquid inside a
narrow capillary tube is not planar. The water falls down in the center
and is elevated at the edge where the liquid touches the walls of the capillary
tube. This is due to the attraction between the liquid and the glass
molecules.
Surface tension is defined as the force per unit length along the
boundary of the surface of the liquid. In a capillary tube of radius R,
the length of the boundary is 2 π R. That is the contact
between glass and liquid. The angle of contact between the glass and liquid
is Ф.
Then the force on the risen column of liquid (of height
h) above normal surface of liquid = S * (2 π R)
The gravitational force acting downward on the column of height h
F = mg = ρ * V * g = ρ * π R² * h * g
As the liquid column is in static equilibrium:
S * 2 π R = π R² ρ g h
h = 2 S /(ρ g R)