Question

Please tell q 4 second part and q 8

Answer 1

ok friend

a)

$\sqrt{3^2\sqrt{9^2\sqrt{81^2 * 4^4} } }\\\sqrt{3^2\sqrt{9^2 *9^2 * 4^4} } } \\{3*{9^2 *9^2 * 4^4} } }\\=> 3 * 9^4 * 256\\=> 9^4 * 768 = 5038848$

b)

$if\ 64^a = \frac{1}{256^a} \\find\ 3a + 4b\\=> 4^3^a = \frac{1}{4^4^b}\\=> 4^3^a = 4^-^4^b\\=> 3a = -4b\\Therefore\ 3a + 4b = -4b + 4b = 0 (Answer)$

Answer 2

Answer:

Correct option is

C

x

2

−2

(x

2

+5)

x

4

+3x

2

−10

=

(x

2

+5)

x

4

+5x

2

−2x

2

−10

=

(x

2

+5)

x

2

(x

2

+5)−2(x

2

+5)

=

(x

2

+5)

(x

2

−2)(x

2

+5)

=(x

2

−2)