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dont know sorry brother really sorry
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%sodium in sample 1=(0.785/2)*100
=39.25
%sodium in sample 2=(1.15/2.925)*100
=39.31
As percentage of sodium and chlorine in both samples is same law of constant proportion is verified.
=39.25
%sodium in sample 2=(1.15/2.925)*100
=39.31
As percentage of sodium and chlorine in both samples is same law of constant proportion is verified.
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