Math, asked by harshita317034, 1 year ago

Please tell question 7

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Answered by kalyaniprasad8
1

Let the parallel side be a and b.

Now,

1/2*(a+b)*15=300

a+b= 600/15= 40

and

a-b=16----------given

Adding,

2a=56

a=28

b=12

Thus, sides are 28 cm and 12 cm

Answered by cyrus14
1

Area of a trapezium A is given by

A = 1/2 (a + b) h

If one side is a, the other side is 'a-16' since the difference of the parallel sides is 16

⇒ 1/2 (a + a - 16) x 15 = 300

1/2 (2a - 16) x 15 = 300 Multiply both sides by 2

(2a - 16)x15 = 600 Divide both sides by 15

2a - 16 = 40

2a = 56

a = 28

28 - 16 = 12

∴ The sides are 28 m and 12 m

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