Question

please tell question no 2 and dont spam it​

Answer 1

Answer:

AOB=55-180=125

3x-5=125

3x=125-5

3x=120

x=120\2

x=40

AOC=40

x+20=125

x=125-20

x=105

DOB=105

Step-by-step explanation:

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Answer 2

Answer:

x=27.5°

Step-by-step explanation:

Since AOB is a straight line

Angle AOB =180°

Thus,angleAOC+angleCOD+angleDOB=180°

(3x-5)+55+(x+20)=180°

3x+x+55+20-5=180°

4x+70=180

4x=180-70

4x=110

x=27.5°

Thus angle AOC

(3×27.5)-5

82.5-5

75.5°

Angle BOD

27.5+20

47.5°