Question

please tell question no. 3

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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• Let the ten's digit be 'x', and unit's digit be 'y'.


• Then, given x + y = 10....[equation i]


• Let the two digit number be 10x + y

• And, number formed by interchanging its digits = 10y + x



• Then, according to the question, number formed by interchanging its digit exceed the original number by 36.

or, new number = original number + 36

=> 10x + y + 36 = 10y + x

=> 10x + y - 10y - x = - 36

=> 10x - x - 10y + y = - 36

=> 9x - 9y = - 36

=> 9 (x - y) = - 36

=> x - y = - 36/9

=> x - y = - 4..... [equation ii]




• Now, adding equations i and ii,

x + y = 10

x - y = - 4
(+) (+) (+)


=> 2x = 6

=> x = 6/2

=> x = 3

• So, x = 3


• Now, putting the value of x in equation i.


=> x + y = 10

=> 3 + y = 10

=> y = 10 - 3

=> y = 7

• So, y = 7



• Therefore, the original number is -

10x + y

= 10(3) + 7

= 30 + 7

= 37.


$<marquee>Hence, your answer is 37.</marquee>$
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Thank you.. ;-)