Question

please tell right answer I will mark you brainlist​

Answer 1

Given: The values angle CAB = angle CED, CE = 10 cm, CD = 8 cm, BE = 2 cm , AB = 9 cm

To find: The value of a+b ?

Solution:

Now we have given angle CAB = angle CED.

Consider the triangles ABC and EDC, we get:

               angle ACB = angle DCE            (common angle)

               angle CAB = angle CED            (given)

So, by AA similarity we can say that triangle ABC similar to triangle DEC.

Now, we know that ratio of sides of similar triangle are same, so:

               AB/DE = BC/CE = AC/DC

Now putting the values on above ratio, we get:

               9 / a  =  12 / 10  =  8 + b / 10

Considering first and second, we get:

               9 / a  =  12 / 10

               9 / a  =  6 / 5

               45 / 6 = a

Now considering second and third, we get:

               12 / 10  =  8 + b / 10

               6/5 = 8 + b / 10

               60/5 = 8 + b

               60/5 - 8 = b

               b = 60 - 40 / 5

               b = 20 / 5

               b = 4

So a + b = 45 / 6 + 4 = 45 + 24 / 6

               a + b = 69/6 = 23/2

Answer:

           So the value of a + b is 23/2

MARK ME AS BRAINLIST PLZZZ...