Question

please tell solutions fast and correct. spammers will be reported. only these 3 answers​

Answer 1

This is the 6th one

Answer:

As Δ ADC ≅ Δ AEB so BE= CD

Step-by-step explanation:

In the given figure

Given : AB = AC -----(i)

          BD = CE ------(ii)

Now

(i) +(ii) we get

AB+ BD= AC+ CE

⇒ AD= AE

Now consider Δ ADC and Δ AEB

AC = AB                              (Given)

AD = AE                              (Proved above)

∠A= ∠A                               (Common)

Therefore  Δ ADC ≅ Δ AEB       (Side - Angle- Side)

BE= CD                                       (C.P.C.T)

Hence, we proved the required result .