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find the zeros of 7x^2+ 49x verify the relationship between zeroes and coefficients
Answers
Answer:
Correct option is
Correct option isB
Correct option isB7
Correct option isB79
Correct option isB79
Correct option isB79 ,
Correct option isB79 , 7
Correct option isB79 , 7−9
Correct option isB79 , 7−9
Correct option isB79 , 7−9
Correct option isB79 , 7−9 49x
Correct option isB79 , 7−9 49x 2
Correct option isB79 , 7−9 49x 2 −81
Correct option isB79 , 7−9 49x 2 −81=(7x)
Correct option isB79 , 7−9 49x 2 −81=(7x) 2
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9)
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=−
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 7
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x=
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 7
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are −
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 7
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 ,
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 7
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79 Relationship between the zeros and the coefficients of the polynomials-
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79 Relationship between the zeros and the coefficients of the polynomials-Sum of the zeros=-
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79 Relationship between the zeros and the coefficients of the polynomials-Sum of the zeros=- coefficient of x
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79 Relationship between the zeros and the coefficients of the polynomials-Sum of the zeros=- coefficient of x 2
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79 Relationship between the zeros and the coefficients of the polynomials-Sum of the zeros=- coefficient of x 2
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79 Relationship between the zeros and the coefficients of the polynomials-Sum of the zeros=- coefficient of x 2 coefficient of x
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79 Relationship between the zeros and the coefficients of the polynomials-Sum of the zeros=- coefficient of x 2 coefficient of x
Correct option isB79 , 7−9 49x 2 −81=(7x) 2 −(9) 2 =(7x+9)(7x−9)x=− 79 , x= 79 The zeros of the polynomials are − 79 , 79 Relationship between the zeros and the coefficients of the polynomials-Sum of the zeros=- coefficient of x 2 coefficient of x =−( 49/0)=0
0)=0Also sum of zeros=−
0)=0Also sum of zeros=− 7/9 + 7/9
9
9 =
9 = 7/−9+9
−9+9
−9+9 =0
−9+9 =0 Product of the zeros =
−9+9 =0 Product of the zeros = coefficient of x
−9+9 =0 Product of the zeros = coefficient of x 2
−9+9 =0 Product of the zeros = coefficient of x 2
−9+9 =0 Product of the zeros = coefficient of x 2 constant term
−9+9 =0 Product of the zeros = coefficient of x 2 constant term
−9+9 =0 Product of the zeros = coefficient of x 2 constant term =
−9+9 =0 Product of the zeros = coefficient of x 2 constant term = 49/−81
−81
−81
−81 Also the product of the zeros=−
−81 Also the product of the zeros=− 7/9
9
9 ×
9 × 7/9
9
9 =
9 = 49/−81
−81
−81
−81 Hence verified.