Question

Please tell the 12th question

Answer 1

Mass of hot water (m1) = 300 g

Temperature (T1) = 50oC

Mass of cold water (m2) = 600 g

Change in temperature of cold water (T − T2) = 15oC

Final temperature = ToC

The specific heat capacity of water is c.

Initial temperature of cold water = 20oC − 15oC = 5oC.

Answer 2

hyy here is ur answer

mass of hot water [m1] = 300 g

tempt. [T1] = 50'c

mass of cold water [m2] = 600 g

Change in tempt. of cold water [T − T2] = 15'c

final temperature = T'c

 specific heat capacity of water is c.

m1c1 [t1-t]=m2c2 [t-t2]

300[50-t]=600[15]

t=20'c

so final temp=20'c

change in temp=15'c

Initial tempt of cold water = 20'c − 15'c = 5'c.

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