Question

please tell the answer ​

Answer 1

Answer:

First, find the prime factors of the given integers: 40, 36 and 126.

For, 40 = 2 x 2 x 2 × 5.

36 = 2 x 2 x 3 x 3.

126 = 2 × 3 × 3 × 7.

Now, L.C.M of 40, 36 and 126 = 23 × 32 × 5 × 7.

∴ L.C.M (40, 36, 126) = 2520.

And, H.C.F (40, 36 and 126) = 2

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