Question

please tell the answer​

Answer 1

Take LCM of 3 and 4= 12

So

[4(x-1)-{3(x-2)}]/12= 1

[4x-4- (3x-6)]=12

x+2=12

x=10

Answer 2

Step-by-step explanation:

Question:-

$Find \: the \: value \: of \: X \: if : ( \frac{x-1}{3} )-( \frac{x-2}{4} ) = 1$

Answer:-

$⇒( \frac{x-1}{3} )-( \frac{x-2}{4}) = 1 \\ \\ ⇒ \frac{4x - 4 - 3x - 6}{12} = 1 \\ \\ ⇒ \frac{4x-3x-4-6}{12} =1 \\ \\ ⇒ \frac{x-10}{12} =1 \\ \\ ⇒x-10= 12×1 \\ \\ ⇒x-10=12 \\ \\ ⇒x = 12+10 \\ \\ ⇒x=22 \: (Ans)$

Therefore, the value of x in above sum is 22.

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