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Answer:
55 degrees = ∆y
Step-by-step explanation:
angle CEF=CFE{∆CEF is isocelses}
Angle CEF+CFE+ECF=180(Angle sum property)
(40)+2×angleCFE=180. (Since Angle CFE=CEF)
Angle CFE= 70
Angle CED = 180-angle CEF(Linear pair)
Angle CED = 180-70
= 110
Angle CED+y+DCE = 180(Angle sum property)
15 + 110 + angle y = 180
angle y = 180-125
= 55 degrees
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