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Answer:
the three pairs of equal parts are
BD=DC
|_ADB
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Step-by-step explanation:
Given,
AB=AC
D is the midpoint of BC
(ie) BD=DC
To prove:
ΔABD ≅ ΔACD,
∠B = ∠C
Proof
In ΔABD and ΔACD,
AD = AD (common)
BD = DC (given)
AB = AC (given)
By SSS cong. rule,
ΔABD ≅ ΔACD,
∠B = ∠C (CPCT)
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