Math, asked by sudarsanseenivasan, 20 days ago

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Answered by ay249021
1

Answer:

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Answered by shaswat8080
0

As all the above questions is on circle following formulas need to keep in mind

area \: of \: circle = \pi \:  {r}^{2}

radius \: of \: circle =  \frac{diamee}{2}

circumference \: of \: circle = 2\pi \: r

1) given that

diameter is 105cm

to find : area of dining

solution

area \: of \: dining = \pi \times ( \frac{105}{2}  {)}^{2}

area of dining is 8659.1 Sq.cm

2)

given that

radius is 2.135mtr

area \: of \: spoted \: circle \:  = \pi \times (2.135 {)}^{2}

hence area of spoted circle is 14.32 Sq.mtr.

3)

given that

area is 1386 Sq.cm

to find radius and diameter

solution

radius =  \sqrt{ \frac{1386}{\pi} }

radius is 21cm

and diameter is 42cm.

4)

given that

circumference of circular park is 352mtr

to find area of park

solution

radius =  \frac{352}{2\pi}

area \: of \: park \:  =  \: \pi \times (56.02 {)}^{2}

area of park is 9859.07 sq.mtr.

5)

given that

length of rope is 4.9m

rope can cover circular area

hence

max \: area \: can \: cover \:  = \pi \times (4.9 {)}^{2}

hence area of rope can cover is 75.429 sq mtr.

6)

given that

area is 2464 sq mtr

to find

length of rope

solution

as rope can cover only circular hence

radius =  \sqrt{ \frac{2464}{\pi} }

radius is 28m

hence length of rope is 28m

7)

given that

radius is 63cm

to find area

solution

area \: of \: carpet \:  = \pi \times (63 {)}^{2}

hence area of carpet is 12468.98Sq.cm

8)

given that

diameter is 49mtr

rate of leveling is 150rs per sq mtr

to find cost of leveling.

solution

area \: ofgarden =  \: \pi \times ( \frac{49}{2}  {)}^{2}

area of garden is 1885.74 sq mtr

cost \: of \: leveling \:  = 1885.74 \times 150

hence total cost is 282861.12rs.

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