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A TV tower stands vertically on the side of a road. From a point on the other side directly opposite to the tower, the angle of elevation of the top of tower is 60
o
. From another point 10m away from this point, on the line joining this point to the foot of the tower, the angle of elevation of the top of the tower is 30
o
.Find the height of the tower and the width of the road.
December 26, 2019avatar
Deboshree Anvar
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In this figure; CD=10m,∠ACB=60
∘
,∠ADB=30∘,AB=? and BD=?
In △ABC,
tan60
∘
=
x
h
3
=
x
h
h=x
3
--------- (1)
In △ABD,
tan30
∘
=
10+x
h
3
1
=
10+x
h
h
3
=10+x ---------- (2)
From equation (1) and (2);
x
3
=
3
10+x
3x=10+x
x=5
,which is the width of the road.
From (1),
h=5
3
m
,which is the height of the tower.
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