Question

please tell the answer​

Answer 1

Heya mate here's your answer

initial velocity u= 0

acceleration a=10m/s ^2

height ,s=20 m ;final velocity(v) and time taken (t)?

by 3rd equation of motion

v^2 = u^2 + 2 as

1. v^2 = 0 +2 × 10 × 20
2. v^2 = 400
3. v^2 = 20 m/s

by 2nd equation of motion

s=ut +1/2 at^2

20 = 0 × t + 1/2 × 10 × t^2

therefore, t^2 = 4

hence t = 2 hence proved

hope it helps you