Question

please tell the answer fast​

Answer 1

Answer:

answer - a=-31 and b= 24$\sqrt{5}$

Step-by-step explanation:

FIND ATTACHMENT HERE OF YOUR ANSWER

Answer 2

Answer:

$given = \: \frac{4 + \sqrt[3]{5} }{4 - \sqrt[3]{5} } = a + \sqrt[b]{5}$

To prove= value of a and b

$\frac{4 + \sqrt[3]{5} }{4 - \sqrt[3]{5} } \times \frac{4 + \sqrt[3]{5} }{4 + \sqrt[3]{5} } = a + \sqrt[b]{5}$

$= \frac{( {4 + \sqrt[3]{5}) }^{2} }{( {4})^{2} - ( { \sqrt[3]{5} })^{2} } = a + \sqrt[b]{5}$

$= \frac{( {4})^{2} + ( { \sqrt[3]{5} })^{2} + 2(4)( \sqrt[3]{5}) }{16 - 45} = a + \sqrt[b]{5}$

$\frac{16 + 45 + \sqrt[24]{5} }{ - 29} = a + \sqrt[b]{5}$

$\frac{61 + \sqrt[24]{5} }{ - 29} = a + \sqrt[b]{5}$

$so \: a = \frac{61}{ - 29} \: and \: b = \frac{24}{ - 29}$

• hope it helps you...
• please mark it as a brainlist answer....
• also please rate thanks and follow me....
• stay home STAY SAFE....