please tell the answer fast
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Heya.............❤✌
Number of O atoms in O2 = 16/32 ×2 × NA = 1×NA
Number of O atoms in O3 = 16/48 ×3 ×NA = 1×NA
Number of O2 atoms in bulb A = 16/32 × NA = 1/2 NA
Number of O3 atoms in bulb B = 16/48 NA = 1/3 NA.
Therefore, option A & D are correct.
Hope it’s helpful....... ☺
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