Math, asked by chhavi9108, 7 months ago

please tell the answer fast​

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Answered by tiltsofsugar
1

Answer:

Step-by-step explanation:

See there are two ways of doing this.

Before I come to that I would like to do few calculations.

Lets assume batsman has played ‘x’ innings . Since his average before the match is 15 . So his total runs will be 15x( avg=total runs/total innings) [ I also need to tell you that I have to make an assumption that the batsmen has never played a “not out” innings, since a “not out “ innings is considered to be an incomplete innings and hence his runs in that innings is summed up to his total runs but their is no incrementation in the no. of innings]

So coming to the calculation part ,

Total runs after x innings=15x

Runs after x+1 innings= 15x+23

So avg= Total Runs/total completed innings

avg=(15x+23)/(x+1)=16

15x+23=16x+16

so, x=7

So total Runs after (x=7) innings=15*7=105

Method 1:

If the batsmen gets out so his no. innings get incremented by one , so his total innings become 8.

so consider he has to score ‘y’ runs in his 8th innings . So by our formula to calculate average

avg= total runs / total completed innings

Since he wants to increase his avg to 18

so , 105+y/8=18

so y=18*8–105

hence y=39

Method 2:

Assuming he remains “not out”, so number of innings is not incremented it remains 7

So let us assume he needs to score ‘z’ runs .

Using formula of average

(105+z)/7=18

z=18*7–105

hence z=21

Hence, If the batsman wants to increase his average to 18, he can do it in two ways either by scoring 39 runs and then geting out, or by scoring 21 runs and remaining “Not out”.

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