Question

please tell the answer fast.

Answer 1

hey bro!
ur Ans!

$= > {x}^{2} + \frac{x}{4} - \frac{1}{8} \\ take \: lcm \\ \\ = > \frac{ 8{x}^{2} + 2x - 1}{8} \\ \\ = > \frac{1}{8} \times 8 {x}^{2} + 4x - 2x - 1 \\ \\ = > \frac{1}{8} \times 4x(2x + 1) - 1(2x + 1) \\ \\ = > \frac{1}{8} \times (4x - 1)(2x + 1) \: ans \\ \\ hope \: its \: helpful$