please tell the answer fast forward
Attachments:
Answers
Answered by
0
Answer:
if sinA=cosB then A+B=90 degree
Answered by
0
Answer:
1)Given , sec theta + tan theta = p
we know that, sec2 theta - tan2 theta = 1
(sec theta + tan theta)(sec theta-tan theta) = 1 [a2-b2=(a+b)(a-b)]
p(sec theta - tan theta) = 1
sec theta - tan theta = 1/p
2) sin A = cos B
sin A = sin (90-B) [ sin (90-theta) = cos theta]
A = 90-B
A+B=90
Similar questions